1. D(y)=(∞;∞)
2. f'(x)=(1/3)*3x²+(1/2)*2x-2*1=x²+x-2
3. D(y')=(-∞;∞)
4. f'(x)=0, x²+x-2=0
x₁=-1, x₂=2
5. f(-2)=(1/3)*(-2)³+(1/2)*2²-2*(-2)+1/2=-8/3+2+4+1/2=23/6
f(1)=1/3+1/2-2+1/2=1/3
f(2)=(1/3)*2³+(1*2)*2²-2*2+1/2
ответ: fнаиб.=f(-2)=23/6
fнаим=f(1)=1/3