\frac{7(x-6)}{4} = \frac{5(x+1)}{3} - 3(x+2); \frac{3(2x+5)}{8} - \frac{2(5x+7)}{3} =...

Question

\frac{7(x-6)}{4} = \frac{5(x+1)}{3} - 3(x+2);

\frac{3(2x+5)}{8} - \frac{2(5x+7)}{3} = \frac{7(x-15)}{4} - 6\frac{7}{8}

Answer 1

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