0\\\\t=\lg x\\ \frac{1}{12}t^2=\frac{1}{3}-\frac{1}{4} t\\ \frac{1}{12}t^2+\frac{1}{4} t-\frac{1}{3}=0|\cdot 12\\ t^2+3t-4=0\\ t^2-t+4t-4=0\\ t(t-1)+4(t-1)=0\\ (t+4)(t-1)=0\\ t=-4 \vee t=1\\\\ \lg x=-4\\ x=10^{-4}\\ x=\frac{1}{10^4}\\ \underline{x=\frac{1}{10000}}\\\\ \lg x=1\\ x=10^1\\ \underline{x=10} " alt=" \\\frac{1}{12}\lg^2x=\frac{1}{3}-\frac{1}{4}\lg x\\\\x>0\\\\t=\lg x\\ \frac{1}{12}t^2=\frac{1}{3}-\frac{1}{4} t\\ \frac{1}{12}t^2+\frac{1}{4} t-\frac{1}{3}=0|\cdot 12\\ t^2+3t-4=0\\ t^2-t+4t-4=0\\ t(t-1)+4(t-1)=0\\ (t+4)(t-1)=0\\ t=-4 \vee t=1\\\\ \lg x=-4\\ x=10^{-4}\\ x=\frac{1}{10^4}\\ \underline{x=\frac{1}{10000}}\\\\ \lg x=1\\ x=10^1\\ \underline{x=10} " align="absmiddle" class="latex-formula">