0} \atop {x+1>0}} \right. \; \to x>-1\\\\\frac{x^2+8}{x+1}=2^3\\\\\frac{x^2+8-8x-8}{x+1}=0\\\\\frac{x(x-8)}{x+1}=0\\\\x_1=0,\; x_2=8" alt="log_5(x^2+8)-log_5(x+1)=3log_52,\; \; \; ODZ:\; \left \{ {{x^2+8>0} \atop {x+1>0}} \right. \; \to x>-1\\\\\frac{x^2+8}{x+1}=2^3\\\\\frac{x^2+8-8x-8}{x+1}=0\\\\\frac{x(x-8)}{x+1}=0\\\\x_1=0,\; x_2=8" align="absmiddle" class="latex-formula">