Решите систему неравенств:

Question

Решите систему неравенств:

0}} \right." alt="\left \{ {{(2+x)^{2}\geq9} \atop {x+2>0}} \right." align="absmiddle" class="latex-formula">

Answer 1

0 \end{cases}" alt="\begin{cases} (2+x)^2\geq9\\x+2>0 \end{cases}" align="absmiddle" class="latex-formula">

 

-2 \end{cases}" alt="\begin{cases} 4+4x+x^2-9\geq0\\x>-2 \end{cases}" align="absmiddle" class="latex-formula">

 

-2 \end{cases}" alt="\begin{cases} x^2+4x-5\geq0\\x>-2 \end{cases}" align="absmiddle" class="latex-formula">

 

-2 \end{cases}" alt="\begin{cases} (x-1)(x+5)\geq0\\x>-2 \end{cases}" align="absmiddle" class="latex-formula">

 

 

      +                                 -                -                          +

----------------------- -5 --------- -2 -------------- 1 -----------------------