Решите премер по действиям )

Решите задачу:

$1)\;5\frac9{11}:1\frac29=\frac{64}{11}:\frac{11}9=\frac{64}{11}\cdot\frac9{11}=\frac{576}{121}\\2)\;7\frac23\cdot1\frac1{23}=\frac{23}3\cdot\frac{24}{23}=\frac{24}3=8\\3)\;\frac{576}{121}-8=\frac{576-968}{121}=-\frac{392}{121}\\4)\;\frac{11}{54}-\frac5{36}=\frac{22-15}{108}=\frac7{108}\\5)\;\frac{576}{121}:\frac7{108}=\frac{576}{121}\cdot\frac{108}7=\frac{62208}{847}=73\frac{377}{847}$