Решить систему уравнения: (2x+3y=3; (x-2y=5;

$\left \{ {{2x+3y=3;} \atop {x-2y=5;}} \right.\\ \left \{ {{2x+3y=3;} \atop {x=2y+5;}} \right.\\ \left \{ {{2(2y+5)+3y=3;} \atop {x=2y+5;}} \right.\\ \left \{ {{4y+10+3y=3;} \atop {x=2y+5;}} \right.\\ \left \{ {{7y+10=3;} \atop {x=2y+5;}} \right.\\ \left \{ {{7y=3-10;} \atop {x=2y+5;}} \right.\\ \left \{ {{7y=-7;} \atop {x=2y+5;}} \right.\\ \left \{ {{y=-1;} \atop {x=2y+5;}} \right.\\ \left \{ {{y=-1;} \atop {x=2*(-1)+5;}} \right.\\ \left \{ {{y=-1;} \atop {x=3}} \right.\\$

ответ: (3;-1)