Плиз помогите. Заполните с помощью формулы y=9/11x

Решите задачу:

$1) \frac{9}{11}\cdot 0,5= \frac{9}{11}\cdot \frac{5}{10} = \frac{9}{11}\cdot \frac{1}{2}= \frac{9}{22}$
$2)\frac{9}{11}\cdot 3 \frac{2}{3} = \frac{9}{11}\cdot \frac{11}{3} = \frac{9\cdot 11}{11\cdot 3}=3$
$3)\frac{9}{11}\cdot 3 \frac{11}{90} = \frac{9}{11}\cdot \frac{281}{90} = \frac{1}{11}\cdot \frac{281}{10}= \frac{281}{110}=2 \frac{61}{110}$
$\frac{9}{11}\cdot 4,73= \frac{9}{11}\cdot \frac{473}{100} = \frac{9}{1}\cdot \frac{43}{100}= \frac{387}{100}=3,87$