t\to 2\end{array}\right] = \lim_{t \to 2} \frac{t^3-8}{4-t^2}= \lim_{t \to 2} -\frac{(t-2)(t^2+2t+4)}{t^2-4}" alt=" \lim_{x \to 64} \frac{\sqrt{x}-8}{4-\sqrt[3]{x}}= \left[\begin{array}{ccc}\sqrt[6]{x}=t\\\sqrt[3]{x}=t^2\\\sqrt{x}=t^3\\x \to 64 =>t\to 2\end{array}\right] = \lim_{t \to 2} \frac{t^3-8}{4-t^2}= \lim_{t \to 2} -\frac{(t-2)(t^2+2t+4)}{t^2-4}" align="absmiddle" class="latex-formula">
