Х×(х+7)= х×(3х+2)+4×(х-1)= х×(1+х+y+d)=

Question

Х×(х+7)=
х×(3х+2)+4×(х-1)=
х×(1+х+y+d)=

Answer 1

Х·(х+7)=x²+7x х·(3х+2)+4·(х-1)=3x²+2x+4x-4=3x²+6x-4
х·(1+х+y+d)=x+x²+xy+xd