Решите систему уравнений методом подстановки: {6x - y = 4 {3x + 5y = 13

$\left \{ {{6x - y = 4} \atop {3x + 5y = 13}} \right;\\ \left \{ {{y=6x-4} \atop {3x + 5y = 13}} \right;\\ \left \{ {{y=6x-4} \atop {3x + 5(6x-4) = 13}} \right;\\ \left \{ {{y=6x-4} \atop {3x + 30x-20) = 13}} \right;\\ \left \{ {{y=6x-4} \atop {33x=20+13}} \right;\\ \left \{ {{y=6x-4} \atop {33x=33}} \right;\\ \left \{ {{y=6x-4} \atop {x=1}} \right;\\ \left \{ {{y=6*1-4} \atop {x=1}} \right;\\ \left \{ {{y=2} \atop {x=1}} \right;\\$

ответ: (1;2)