1)(x-2)(x+2)(2x-1)<0<br>x=2 x=-2 x=1/2
_ + _ +
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-2 1/2 2
x∈(-∞;-2) U (1/2;2)
2)(3-y)(3+y)(6-5y)≥0
y=3 y=-3 y=1,2
_ + _ +
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-3 1,2 3
y∈[-3;1,2] U [3;∞)
3)(x-1)(x+2)(3x-1)>0
x=1 x=-2 x=1/3
_ + _ +
---------------------------------------------------
-2 1/3 1
x∈(-2;1/3) U (1;∞)
4)(2x-5)(x+0,5)(3x+7)≤0
x=2,5 x=-0,5 x=-7/3
_ + _ +
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-7/3 -0,5 2,5
x∈(-∞;-7/3} U [-0,5;2,5]