2/3+4/5; 23/8+13/4: 3-17/9: 31/2+1/3: 1 1/5-3/4;

Решите задачу:

$\frac{2}{3} + \frac{4}{5} = \frac{2*5+4*3}{15}= \frac{22}{15} =1 \frac{7}{15}\\\frac{23}{8} + \frac{13}{4} = \frac{23+13*2}{8} = \frac{49}{8} =6 \frac{1}{8}\\3- \frac{17}{9} = \frac{27}{9} - \frac{17}{9} = \frac{10}{9} =1 \frac{1}{9}\\\frac{31}{2} + \frac{1}{3} = \frac{31*3+1*2}{6} = \frac{95}{6} = 15 \frac{5}{6}\\1 \frac{1}{5} - \frac{3}{4} = \frac{6*4-3*5}{20}= \frac{9}{20}$