(4x+3)(4x-3)-(6x-1)^2+18=0 РЕШИТЬ

Question

(4x+3)(4x-3)-(6x-1)^2+18=0 РЕШИТЬ

Answer 1

Решение
(4x+3)(4x-3)-(6x-1)^2+18=0
16x² - 9 - 36x² + 12x - 1 + 18 = 0
- 20x² + 12x + 8 = 0
4x² - 6x - 4 = 0 
2x² - 3x - 2 = 0
D = 9 + 4*2*2 = 25
x₁ = (3 - 5)/4
x₁ = -1/2
x₂ = ( 3 + 5)/4
x₂ = 2
Ответ: x₁ = -1/2 ; x₂ = 2