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Решите задачу:

$\left \{ {{y-5x=1} \atop {y^2-13x=23}} \right. \; \left \{ {{y=5x+1} \atop {(5x+1)^2-13x=23}} \right. \\\\25x^2-3x-22=0\\\\D=2209,\sqrt{D}=47\\\\x_1=\frac{3-47}{50}=-\frac{44}{50}=-\frac{22}{25}\\\\x_2=\frac{3+47}{50}=1\\\\y_1=-5\cdot \frac{22}{25}+1=\frac{-22+5}{25}=-\frac{17}{5}\\\\y_2=5\cdot 1+1=6\\\\Otvet:\; (-\frac{22}{25};-\frac{17}{5}),\; (1,6).$