Решите неравенство x+4>3-2x 3-x/2 + x/4 > 7 (/- дробь)

$1)$
$x+4\ \textgreater \ 3-2x$

$x+2x\ \textgreater \ 3-4$

$3x\ \textgreater \ -1$

$x\ \textgreater \ - \frac{1}{3}$

------------(-1/3)-----------------------
//////////////////////////

Ответ: $(- \frac{1}{3};+$ ∞ $)$

$2)$

$3- \frac{x}{2}+ \frac{x}{4}\ \textgreater \ 7$

$- \frac{x}{2}+ \frac{x}{4}\ \textgreater \ 7-3$

$- \frac{2x}{4}+ \frac{x}{4}\ \textgreater \ 4$

$- \frac{x}{4}\ \textgreater \ 4$

$-x\ \textgreater \ 16$

$x\ \textless \ -16$

----------------(-16)----------------
////////////////

Ответ: $(-$ ∞ $;-16)$