Помогите прошу! Математика

$\frac{5}{2x+1} + \frac{x}{2x-1} = \frac{14}{1-4 x^{2} }$
$\frac{5(2x-1)+x(2x+1)}{(2x+1)(2x-1)} = \frac{14}{1-4 x^{2} }$
$\frac{5(2x-1)+x(2x+1)}{4 x^{2} -1} = \frac{14}{1-4 x^{2} }$
$\frac{-(5(2x-1)+x(2x+1))}{1-4 x^{2} } = \frac{14}{1-4 x^{2} }$
$-(5(2x-1)+x(2x+1)) = 14$
10x-5+2x²+x=-14
2x²+11x+9=0
D=11²-4*2*9=121-72=49
x₁=(-11+7)/4=-1
x₂=(-11-7)/4=-18/4=-4.5