(sin68+cos38)^2+(sin38-cos68)^2=? решите очень надо

Question

(sin68+cos38)^2+(sin38-cos68)^2=?
решите очень надо

Answer 1

Sin²68+2sin68cos38+cos²38+sin²38-2sin38Cos68+cos²68=(sin²38+cos38)+(sin²68+cos68)+2(sin68cos38-sin38cos68)=1+1+2(sin(68-38))=2+2sin30=2+2*0,5=2+1=3

Answer 2

(sin68+cos38)^2+(sin38-cos68)^2=sin^268 +2sin68cos38 + cos^238 + sin^238 - 2sin38cos68+cos^268=(sin^268 +cos^268) + (sin^238 +cos^238)+2(sin68cos38-sin38cos68)=1+1+2sin(68-38)=2+2sin30=3