(2x2 + 3)2 – 12(2x2 + 3) + 11 = 0

Question

(2x2 + 3)2 – 12(2x2 + 3) + 11 = 0

Answer 1

(2x^2 + 3)^2 – 12(2x^2 + 3) + 11 = 0

замена 2x^2+3=t

t^2-12t+11=0

D=100

t=1

t=11

 

2 случая:

1) 2x^2+3=1

2x^2=-2

x^2=-1

нет реш

 

2) 2x^2+3=11

2x^2=8

x^2=4

x=±2