1)y`=6x-6x²=0
6x(1-x)=0
x=0∈[-4;0]
x=1∉[-4;0]
y(-4)=48+128+1=177наиб
y(0)=1наим
2)y`=8x-4-3x²
D=64-48=16
x1=(-8-4)/(-6)=2∈[1;3]
x2=(-8+4)/(-6)=2/3∉[1;3]
y(1)=4-4-1=-1
y(2)=16-8-8=0наиб
y(3)=36-12-27=-3наим
3)y`=3x²-4x+1=0
D=16-12=4
x1=(4-2)/6=1/3∉[1;4]
x2=(4+2)/6=1∈[1;4]
y(1)=1-2+1+5=5наим
y(4)=64-32+4+5=41наиб