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Решите задачу:

$\int\limits {6 x^{3} *(3 x^{4}-1 )^2} \, dx = \\ \\ = \int\limits {6x^3*(9x^8-6x^4+1)} \, dx = \\ \\ = \int\limits {(54x^{11}-36x^7+6x^3)} \, dx = \\ \\ = 54\int\limits {x^{11}} \, dx -36 \int\limits {x^7} \, dx +6 \int\limits {x^3} \, dx = \\ \\ =54* \frac{x^{12}}{12} -36* \frac{x^8}{8} +6* \frac{x^4}{4}+C= \\ \\ = 4,5x^{12}-4,5x^8+1,5x^4+C.$