Найдите натуральное число,удовлетворяющее неравенству 2целых1/7<х+1целая2/7<3целых1/2

$2 \frac{1}{7}\ \textless \ x+1 \frac{2}{7}\ \textless \ 3 \frac{1}{2}\\\\ 2 \frac{1}{7}-1 \frac{2}{7}\ \textless \ x\ \textless \ 3 \frac{1}{2} -1 \frac{2}{7}\\\\ \frac{15}{7}- \frac{9}{7}\ \textless \ x\ \textless \ \frac{7}{2}- \frac{9}{7}\\\\ \frac{6}{7}\ \textless \ x\ \textless \ \frac{49-18}{14}\\\\ \frac{6}{7}\ \textless \ x\ \textless \ \frac{31}{14} \\\\\frac{6}{7}\ \textless \ x\ \textless \ 2\frac{3}{14} \\\\x\in N$

x∈{1;2}

Ответ: 1; 2