Решите уравнение:4t4-7t2+3=0
t^2=a
4a^2-7a+3=0
D=49-48=1
a=7-1/4*2=3/4 a2=7+1/8=1 t^2=1 t=1;-1
t^2=3/4 t=koren`3/4; -k3/4