Решить уравнение sin3x*sinx+cos3x*cosx=-1
Sin3x sinx + cos3x cosx = -1 cos(3x-x) - cos(3x+x) + cos(3x+x)+cos(3x-x) = -1 2 2 cos2x - cos4x + cos4x + cos2x = -1 2 2cos2x = -1 2 cos2x = -1 2x =π + 2πn x=π/2 + πn Ответ: π/2 + πn