Вопрос в картинках...

Решите задачу:

$\frac{1}{x+ \frac{1}{1+ \frac{x+2}{x-2} } } = \frac{12}{12x-7}$

$12x-7 = {12}*({x+ \frac{1}{1+ \frac{x+2}{x-2} })$

$12x-7 = {12x}{+ \frac{12}{1+ \frac{x+2}{x-2} }$

$-7 = \frac{12}{1+ \frac{x+2}{x-2} }$

$-7 * ({1+ \frac{x+2}{x-2} }) = {12}$

$\frac{-7(x+2)}{x-2} } = {19}$

${-7(x+2)} = {19}(x-2)$

$-7x-14 = 19x-38$

$38-14 = 19x+7x$

$26x = 24$

$x = \frac{12}{13}$