√(x + 1) = √ ( 2x + 3)
√(x + 1) - √(2x + 3) = 0
( x + 1) - ( 2x + 3 ) = 0²
x + 1 - 2x - 3 =0
- x = - 1 + 3
- x = 2
x = - 2
√ ( x - 2) + 3 = 0
√( x - 2) = - 3
x - 2 = ( - 3)²
x - 2 = 9
x = 9 + 2
x = 11
√(2x - 1) = x - 2
(2x - 1) = (x - 2)²
2x - 1 = (x - 2)(x - 2)
2x - 1 = x² - 2x - 2x + 4
2x - 1 = x² - 4x + 4
2x - x² + 4x = 1 + 4
- x² + 6x = 5
- x² + 6x - 5 = 0
x² - 6x + 5 = 0
D = b² - 4ac = ( - 6)² - 4 × 1 × 5 = 36 - 20 = 16 = 4²
x₁ = 6 + 4 / 2 = 5
x₂ = 6 - 4 / 2 = 1
√(3 - x) = - 2
3 - x = ( - 2)²
3 - x = 4
- x = 4 - 3
-x = 1
x = - 1
√y = - 1
y = ( - 1)²
y = 1