2sin(7пи/2-x)*sinx=cosx

Question

2sin(7пи/2-x)*sinx=cosx

Answer 1

-2cosxsinx-cosx=0
-cosx(2sinx+1)=0
cosx=0
x=pi/2+pi*n
2sinx+1=0
sinx=-1/2
x=(-1)^(n+1)*pi/6+pi*n