1)x>15/(x+2)
(x²+2x-15)/(x+2)>0
x²+2x-15=0⇒x1+x2=-2 U x1+x2=-15⇒x1=-5 U x2=3
x+2=0⇒x=-2
_ + _ +
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-5 -2 3
x∈(-5;-2) U (3;∞)
2)(x²-2x+6)/(x+1)>x
(x²-2x+6-x²-x)/(x+1)>0
(6-3x)/(x+1)>0
6-3x=0⇒3x=6⇒x=2
x+1=0⇒x=-1
_ + _
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-1 2
x∈(-1;2)
3)(6x²-15x+19)/(3x²-6x+7)<2<br>(6x²-15x+19-6x²+12x-14)/(3x²-6x+7)<0<br>(5-3x)/(3x²-6x+7)<0<br>5-3x=0⇒3x=5⇒x=5/3
3x²-6x+7=0
D=36-84=-48<0⇒3x²-6x+7>0 при любом х
5-3x<0<br>x>5/3
x∈(5/3;∞)