Помогите пожалуйста,очень надо

Решите задачу:

$log_5(4x+1)\ \textgreater \ -1\; ;\; \; \; ODZ:\; 4x+1\ \textgreater \ 0,\; x\ \textgreater \ -\frac{1}{4}\\\\log_5(4x+1)\ \textgreater \ log_55^{-1}\; ,\; \; \; 5^{-1}=\frac{1}{5}\\\\4x+1\ \textgreater \ \frac{1}{5}\\\\4x\ \textgreater \ -\frac{4}{5}\\\\x\ \textgreater \ -\frac{1}{5}\\\\T.k.\; \; -\frac{1}{5}\ \textgreater \ -\frac{1}{4}\; ,to\; \; otvet:\; x\ \textgreater \ -\frac{1}{5}\; \; ili\; \; x\in (-\frac{1}{5}\, ;+\infty).$