{x≠0
{2 - x²+4 ≥0
2x
{6+x≥0
2 - x²+4 ≥0
2x
4x-x²-4 ≥0
2x
-(x²-4x+4) ≥0
2x
(x-2)² ≤0
2x
2x(x-2)(x-2) ≤0
x=0 x=2
- + +
------------- 0 ------------ 2 ----------------
\\\\\\\\\\\\\\
x∈(-∞; 0)
6+x≥0
x≥-6
{x∈(-∞; 0)
{x≥-6
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
---------- -6 --------------- 0 -----------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-6; 0)
х={-6; -5; -4; -3; -2; -1;}
сумма=-6-5-4-3-2-1=-21
Ответ: -21