(2x² -5x+2)/(x+4) <0 ; * * * ax² +bx+c =a(x -x₁)(x -x₂) * * *<br>2(x-1/2)(x-2)/(x+4) <0 ⇔(x+4)(x-1/2)(x-2) <0 ;<br>методом интервалов :
- + - +
--------- (-4) ------- (1/2)--------- (2) ----------
x∈ (-∞ ; -4) U (1/2 ; 2) .
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Loq(1/3) (2x -1) ≥ -2 ; * * * 0 <2x -1 ≤ (1/3)^(-2) * * *<br>- Loq(3) (2x -1) ≥ -2
Loq(3) (2x -1) ≤ 2 ;
0 <2x -1 ≤ 3² ;<br>1<2x ≤ 10 ;<br>1/2 x ∈ (0,5 ; 5 ] .