1) (x+6)(x+3)((x+2)²+1) ≥ 0 ;* * * (x+2)²+1≥1* * *
(x+6)(x+3)) ≥0;
+ - +
-------- [-6] ------ -----[ -3] -------
ответ: x∈ (-∞; -6] U [-3; ∞).
2) { 5х+у= -7 ;(х+4) ( у- 5) = - 4⇔{ y = -5x-7 ; (x+4)( -5x-7 -5) = - 4 .
{ y = -5x-7 ; (x+4)( 5x+12) = 4.
(x+4)( 5x+12) = 4.
5x² +32x +44 =0 ;
D/4 =(32/2)² -5*44 =256 -220 =36 =6².
x = (-16 ± 6)/5 ;
x₁ =(-16 -6)/5 = - 22/5. * * *-4,4 * * *
x₂ =(-16+6)/5 = -2 .
y = -5x-7 .
y₁ =5(-22/5) -7 = -22-7 =-29.
y₂ =5(-2 ) -7 = - 17.