Помогите решить неравенство двумя способами: 0<3x<2 1<x+4<2

0<3x<2 | :3<br>0/3 < 3x/3 < 2/3<br>0
$\left \{ {{3x\ \textgreater \ 0} \atop {3x\ \textless \ 2}} \right. \\\left \{ {{x\ \textgreater \ 0} \atop {x\ \textless \ \frac{2}{3} }} \right.$

x∈(0; $\frac{2}{3}$ )

11-4 < x+4-4 < 2-4<br>-3
$\left \{ {{x+4\ \textgreater \ 1} \atop {x+4\ \textless \ 2}} \right. \\ \left \{ {{x\ \textgreater \ -3} \atop {x\ \textless \ -2}} \right.$

x∈(-3;-2)