3)
а) tqx =-1 ⇒x = - π/4 +π*k ,k∈Z.
б) ctqx =-1⇒x =- π/4 +π*k ,k∈Z.
в) tqx =-√3 ⇒x = -π/3 +π*k ,k∈Z.
г) ctqx =1/√3 ⇒x = π/3 +π*k ,k∈Z.
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4)
а) tq(x/3+π/4) =√3 ;
x/3 +π/4 =π/3 + π*k ;
x +3π/4 +π + 3π*k ;
x= -π/4 +3π*k; k∈Z.
б)
ctq3x = - 3 ;
3x =(π -arctq3)+ π*k ;
x =1/3*(π -arctq3)+ π/3*k ;k∈Z.