(3+m)(m^2-3m+9)-m(m-2)^2=?

Question

(3+m)(m^2-3m+9)-m(m-2)^2=?

Answer 1

(3+m)(m²-3m+9)-m(m-2)²=(m+3)(m²-3m+9)-m(m²-4m+4)=
=m³+3³-m³+4m²-4m=4m²-4m+27