Sin^2x=1\2 Решите срочно!!!!!!!!!!!!!!!!!!!!!!!!!

Sin²x = 1/2
sin²x - 1/2 = 0
sin²x - (√2/2)² = 0
(sin x - √2/2) * (sin x + √2/2) = 0
1.
sin x - √2/2 = 0
sin x = √2/2
x = $(-1)^{k$ + $\frac{ \pi }{4}$ + $\pi$ k
2.
sin x + √2/2 = 0
sin x = - √2/2
x = $(-1)^{k+1$ + $\frac{ \pi }{4}$ + $\pi$ k
Ответ: x = $(-1)^{k$ + $\frac{ \pi }{4}$ + $\pi$ k и
x = $(-1)^{k$ + $\frac{ \pi }{4}$ + $\pi$ k