Y = 2x^3 - 3x^2 + 10 [ - 2; 1]
y ' = (2x^3 - 3x^2 + 10) ' = 6x^2 - 6x
y ' = 0 ==> 6x^2 - 6x = 0
x^2 - x = 0
x(x - 1) = 0
x = 0 ;
x = 1
y(-2) = -2*8 - 3*4 + 10 = - 16 - 12 + 10 = - 28 + 10 = - 18 == > наим
y(0) = 10; ==> наиб
y(1) = 2 - 3 + 10 = 9
Ответ:
y(-2) = - 18;
y(0) = 10