Придумайте и решите 8 примеров с обыкновенными дробями.

Решите задачу:

$1) \frac{1}{2}+ \frac{1}{2}= \frac{2}{2} = 1$
$2) \frac{1}{3} + \frac{2}{6} = \frac{2}{6} + \frac{2}{6} = \frac{4}{6} = \frac{2}{3}$
$3) \frac{9}{5} - \frac{2}{3} = \frac{27}{15} - \frac{10}{15} = \frac{17}{15}=2 \frac{2}{5}=2,4$
$4) \frac{6}{7}* \frac{4}{6}= \frac{6*4}{7*6} = \frac{24}{42} = \frac{4}{7}$
$5) \frac{1}{2} * \frac{2}{1} = \frac{1*2}{2*1} = \frac{2}{2}=1$
$6) \frac{12}{16}: \frac{2}{4}= \frac{12}{16}* \frac{4}{2} = \frac{12*4}{16*2} = \frac{24}{32} = \frac{3}{4}$
$7) \frac{3}{4} : \frac{3}{4}= \frac{3}{4} * \frac{4}{3}= \frac{3*4}{4*3} = \frac{12}{12} =1$
$8) \frac{2}{3} *( \frac{1}{2}- \frac{5}{6} + \frac{3}{4}):2= \frac{2}{3}*( \frac{6}{12} - \frac{10}{12} + \frac{9}{12}):2= \frac{2}{3} * \frac{5}{12}:2 = \frac{2*5}{3*12}:2$ $= \frac{10}{36}:2= \frac{5}{18}: \frac{2}{1} = \frac{5}{18} * \frac{1}{2}= \frac{5}{36}$