F(x)=-3*x² (0;2)
f(x₀)=-3*x₀²
f`(x₀)=-6x₀
y=f(x₀)+f`(x₀)*(x-x₀) - уравнение касательной.⇒
2=-3*x₀²-6*x₀*(0-x₀)
x₀²=2/3
x₁=√(2/3) x₂=-√(2/3)
k₁=f`(-√(2/3))=6*√(2/3)
k₂=f`(√(2/3))=-6*√(2/3)
tgα=I(k₁-k₂)/(1+k₁*k₂)I=I(12*√(2/3)/(1-24))I=I-12*√(2/3)/23I=12*√(2/3)/23.
tgα=12*√(2/3)/23.