Log7 (x-1)≤ log7 2+log7 3

Question

Log7 (x-1)≤ log7 2+log7 3

Answer 1

Log7(x-1)<=log7(2)+log7(3)<br>log7(x-1)<=log7(2*3)<br>x-1<=6<br>x<=5<br>x=[-бесконечности;5]