Решить пример (12 целых 1/3 - 7 целых 3/4)*6/11 (2 целых 3/5 -5/8)/19 целых 3/4

Решите задачу:

$(12 \frac{1*4}{3*4} -7 \frac{3*3}{4*3} )* \frac{6}{11} = 3 \frac{7}{12} * \frac{6}{11} = \frac{43}{12}* \frac{6}{11}= \frac{43}{22} =1 \frac{21}{22} \\ (2 \frac{3}{5} - \frac{5}{8} ):19 \frac{3}{4} =( \frac{13*8}{5*8} - \frac{5*5}{8*5}) : \frac{79}{4} = \frac{104-25}{40}* \frac{4}{79} = \frac{79}{40} * \frac{4}{79} = \frac{1}{10} =0,1$