1) W(NaOH)в р-ре =108,7/(100+108,7)=0,52(52%).
2) m(NaOH)в 40г р-ра =0,52*40=20,8г;
m(H2О)=40-20,8=19,2г.
ответ: 20,8г щелочи; 19,2г воды.
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