Cos2x =sin (П+ x) решите плизз
Cos2x =sin(π+x) ; 1 -2sin²x = -sinx ; 2sin²x -sinx -1 =0 ; * * * t = sinx , -1 ≤ t ≤ 1 * * * [ sinx = -1/2 ; sinx =1 . [ x =(-1)^(n+1)π/6+πn ; x=π/2+2πn , n∈Z. ответ : (-1)^(n+1)π/6+πn ; π/2+2πn , n∈Z.