Помогите с номером 7 ! во вложении!
a)=(a^6/4*b^7/4)/(a^2/4*b^3/4)=(a^3/2*b^7/4)/(a^1/2*b^3/4)=a^(3/2-1/2)*b^(7/4-3/4)=a*b
б)=(2^4/3*x^5/3*y^2/3)/(2^1/3*x^2/3*y^2/3)=2^(4/3-1/3)*x^(5/3-2/3)*y^(2/3-2/3)=2x
в)=((2^6/5*x^2/5)/y^3/5)*(x^3/5)/(2^1/5*y^2/5)=((2^6/5-1/5)*x^(2/5+3/5))/y^(3/5+2/5)=2x/y
г)=((2^1/4*b^2/4)/a^3/4))*(2^3/4*b^2/4)/a^1/4=(2^(1/4+3/4)*b^(2/4+2/4))/a^(3/4+1/4)=2b/a
д) =((2*x^2/3)/y)*(x^1/3)/y=2*x^(2/3+1/3)/y^2=2*x/y^2
Спасибо!
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