(1/4)^7-х=(1/2)^10 Пжлсь

Question

(1/4)^7-х=(1/2)^10
Пжлсь

Answer 1

Решение:
(1/4)^ (7-x)=(1/2) ^ 10
[(1/2)^2]^ (7-x)=(1/2)^ 10
(1/2)^ (2*7 -2*x)=(1/2)^ 10
(1/2)^ (14-2x)=(1/2)^ 10
14-2x=10
-2х=10-14
-2х=-4
х=-4 : -2
х=2

Ответ: х=2