(2x-5)^2-36=0 помогите(

Question

(2x-5)^2-36=0
помогите(

Answer 1

( 2x - 5)² - 36 = 0
(2x - 5)(2x - 5) - 36 = 0
4x² - 10x - 10x + 25 - 36 = 0
4x² - 20x - 11 = 0
D = b² - 4ac = ( - 20)² - 4 × 4 × ( - 11) = 400 + 176 = 576 = 24²
x₁ =( 20 + 24) / 8 = 44/8 = 5,5
x₂ = (20 - 24) / 8 = - 4 / 8 = - 0,5