Log16 sin p/12 + log16 cos p/12 чему равно
Log₁₆sin(π/12)+log₁₆cos(π/12)=log₁₆[sin(π/12)cos(π/12)]=(1/2)log₄[(1/2)sin(π/6)]= (1/2)log₄[(1/2)×(1/2)]=(1/2)log₄(1/4)=-(1/2)log₄4=-1/2