ПОМОГИТЕ СРОЧНО!!! БУДУ БЛАГОДАРНА.

Question

ПОМОГИТЕ СРОЧНО!!! БУДУ БЛАГОДАРНА.

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Comments

(x²+5)/(25 -x²) = (x²+5)/ (-(x² -25)) = -(x²+5)/(x²-25) =-(x²+5)/(x-5)(x+5) = -(x²+5)/(x² -25) ;(x+1)/(x-5) = (x+1)(x+5)/(x-5)(x+5) = (x²+6x+5)/(x² -25) ;(x-1)/(x-5) =(x-1)(x+5)/(x-5)(x+5) = (x² +4x -5)/(x² -25) .

Answer 1

(x²+5)/(25 -x²) = (x²+5)/ (-(x² -25)) =  -(x²+5)/(x²-25) =-(x²+5)/(x-5)(x+5)   =  -(x²+5)/(x² -25) ;
(x+1)/(x+5) = (x+1)(x-5)/(x-5)(x+5)  =         (x²-4x+5)/(x² -25) ;
(x-1)/(x-5) =(x-1)(x+5)/(x-5)(x+5) =            (x² +4x -5)/(x² -25) .

Answer 2

(X^2+5)/(x+5)(x-5)
(X+1)(x-5)/(x+5)(x-5)
(X-1)(x+5)/(x+5)(x-5)