Вспоминаем одну интересную формулу.
√(a^2) = |a|
√(5x+8)^2 = √(3x-11)^2
Возводим в квадрат, убираем корни и раскрываем скобки.
25x^2 + 80x + 64 = 9x^2 - 66x + 121
16x^2 + 146x - 57 = 0
D/4 = 73^2 - 16*(-57) = 5329 + 912 = 6241 = 79^2
x1 = (-73 - 79)/16 = -152/16 = -19/2
|5(-19/2) + 8| = |-95/2 + 8| = |(-95+16)/2| = |-79/2| = 79/2
|3(-19/2) - 11| = |-57/2 - 11| = |(-57-22)/2| = |-79/2| = 79/2
x2 = (-73 + 79)/16 = 6/16 = 3/8
|5*3/8 + 8| = |15/8 + 8| = |(15+64)/8| = |79/8| = 79/8
|3*3/8 - 11| = |9/8 - 11| = |(9-88)/8| = |-79/8| = 79/8