а) (-1;3) и (2;-2)
(x+1)/(-1-2)=(y-3)/(3+2)
(x+1)/(-3)=(y-3)/5
5x+5+3y-9=0
5x+3y-4=0
б) (4;1) и (-3;-1)
(x-4)/(4+3)=(y-1)/(1+1)
(x-4)/7=(y-1)/2
2x-8=7y-7
2x-8-7y+7=0
2x-7y-1=0
в) (0;5) и (4;0)
(x-0)/(0-4)=(y-5)/(5-0)
x/(-4)=(y-5)/5
5x=-4y+20
5x+4y-20=0
г) (-3;0) и (0;-6)
(x+3)/(-3-0)=(y-0)/(0+6)
(x+3)/(-3)=y/6
6x+18+3y=0